A: Torque can informally be thought of as a “rotational force” or “angular
force” that causes a change in rotational motion. In static-holding
applications, the torque needed for a brake to hold the load is the result
of linear force multiplied by a radius.
There are several applications that may need special calculations, but
a few examples and guidelines illustrate how to properly size a brake for
a broad array of static-holding scenarios.
1. The brake specified should always be at the high-speed end of the
anticipated needs if the application has a motor, gearbox, and drive. The
brake should also mount at the motor, rather than at the load, which
allows use of a smaller brake.
To calculate the necessary torque to hold the load, work backwards
from the load. As an example, suppose the gearbox-output torque T is
250 lb-in. and that level is required to drive the load. Then the holding
torque TH would be:
TH = (T/GR) K
where GR = gear ratio and K = service factor. The service factor is a way
to account for brake wear. The higher the factor, the less the wear. It
should be 1.5 to 3 depending on application data. If K is 1.5, then
TH = 250/10 1.5 = 25 1.5 = 37.5 lb-in.
2. Now consider applications where a motor is driving the load
through a ball screw or leadscrew. A ball screw is more efficient, so
it will probably need more holding torque than a leadscrew. But the
needed holding torque demanded of the brake will vary depending on
the type of ball or leadscrew. The determination of the proper brake
size may involve efficiency, inertia, speed, and several other factors too
numerous to go into here. But the end result should be multiplied by a
service factor, usually 1.5. There is a tool at linearmotioneering.com that
walks through the calculations for this case.
3. In some applications the brake must mount on an arm to keep
a load from falling when power is
removed. Simply calculate the torque
needed to hold the weight of the
arm plus the load (force distance).
Again, then multiply by a service
factor of 1.5.
4. In applications where you know
the motor’s horsepower but little idea
of the loads or holding torque, use
a general formula to get in the right
ballpark of brake selection:
TH = 1.25 63,024 ((P K)/ω)
where 1.25 = a factor added to account for holding the load, in addition
to stopping; P = motor output power, hp; ω = motor speed, rpm; and
K = the service factor which can be
1.5 to 3. The 63,024 is a conversion
factor to give torque in lb-in. It is the
product of 5,252 rpm/lb-ft 12 in./ft.
Rocco Dragone
| Rocco Dragone is a Thomson
Deltran Product Specialist
with Danaher Motion Corp.
Got a question about motion
control or mechatronics? Ask
Rocco via e-mail at Editorial@
DanaherMotion.com. |